C program to check odd or even and check any integer that divisible by another integer value

C program to check odd or even: In childhood As you have studied in mathematics that in decimal number system even numbers are divisible by 2 while odd are not divisible by 2, we may use modulus operator(%) which returns remainder, For example, 7%2 gives 1 ( remainder when seven is divided by two). Even numbers are of the form 2*X and odd are of the form (2*X+1) where X is is an integer.We will determine whether a number is odd or even by using different methods all are provided with a code in c language.

C program to check odd or even using modulus operator

#include <stdio.h>

int main()
{
   int a;

   printf("Enter an integer\n");
   scanf("%d", &a);

   if (a%2 == 0)
      printf("Even\n");
   else
      printf("Odd\n");
   getch();            //This function holds your screen to see result.
   return 0;
}

Find odd or even using conditional operator

#include <stdio.h>

int main()
{
   int n;

   printf("Input an integer\n");
   scanf("%d", &n);

   n%2 == 0 ? printf("Even\n") : printf("Odd\n");

   return 0;
}

C program to check odd or even without using bitwise or modulus operator

#include <stdio.h>
&nbsp;
int main()
{
   int n;
   printf("Enter an integer\n");
   scanf("%d", &n);

   if ((n/2)*2 == n)
      printf("Even\n");
   else
      printf("Odd\n");

   return 0;
}

In C programming language when we divide two integers we get an integer result, For example, the result of 10/3 will be 3. So we can take advantage of this and may use it to find whether the number is odd or even. Consider an integer n we can first divide by 2 and then multiply it by 2 if the result is the original number then the number is even otherwise the number is odd. For example 11/2 = 5, 5*2 = 10 (which is not equal to eleven), now consider 12/2 = 6 and 6*2 = 12 (same as original number). These are some logic which may help you in finding if a number is odd or not.

Find odd or even using conditional operator

#include<stdio.h>

main()
{
   int a;

   printf("Enter an integer\n");
   scanf("%d",&a);

   a%2 == 0 ? printf("Even number\n") : printf("Odd number\n");
   return 0;
}

We can use bitwise AND (&) operator to check odd or even, as an example consider binary of 7 (0111) when we perform 7 & 1 the result will be one and you may observe that the least significant bit of every odd number is 1, so ( odd_number & 1 ) will be one always and also ( even_number & 1 ) is zero.

C program to check odd or even using bitwise operator

#include <stdio.h>

int main()
{
   int a;

   printf("Enter an integer\n");
   scanf("%d", &a);

   if (a & 1 == 1)
      printf("Odd\n");
   else
      printf("Even\n");

   return 0;
}

To check the given no. is even or odd without using the % operator

#include <stdio.h>;

main()
{
  char *a[]={"Odd", "Even"};
  int n;
  printf("Enter an integer\n");
  scanf("%d",&n);

  printf("%s\n", a[(n/2)*2 == n]);

  return 0;
}

To check the given no. is divisible by 3 and also divisible by 5 (Using bitwise and operator)

 #include<stdio.h>
  main()
  {
     int n;
     printf("Eneter any integer value \n");
     scanf("%d",&n);
     
     if(n%3==0 && n%5==0)
     {
        printf("Entered integer is divisible by both 3 and 5");
     }
     else
     {
        printf("Entered integer is not divisible by both 3 and 5");
     }
     return 0;
  }

Output