C Program calculates the sum & average of an array

In the previous tutorial, we have  seen the array definition, declaration, initialization and access array values. Now we use the array to solve real-life math problems.

C Program calculates the sum & average of an array:

In this program, you can able to calculate sum & average of an array. Including classified positive and negative sum.

#include <stdio.h>

void main() 
{
    int array[10];
    int i, num, negative_sum = 0, positive_sum = 0;
    float total = 0.0, average;
    clrscr();
    printf ("Enter the value of N \n");
    scanf("%d", &num);
    printf("Enter %d numbers (-ve, +ve and zero) \n", num);
    for (i = 0; i < num; i++) 
    {
         scanf("%d", &array[i]);           //Inseting value into array
    }
    printf("Input array elements \n");
    for (i = 0; i < num; i++)
    {
         printf("%+3d\n", array[i]);
    }

   /* Summation starts here*/

    for (i = 0; i < num; i++) 
    {
        if (array[i] < 0) 
        {
            negative_sum = negative_sum + array[i];    // Calculate nevative sum
        } 
        else if (array[i] > 0) 
        {
            positive_sum = positive_sum + array[i];    // Calculate positive sum
        } 
        
        total = total + array[i] ;
    }
    average = total / num;
    printf("\n Sum of all negative numbers = %d\n", negative_sum);
    printf("Sum of all positive numbers = %d\n", positive_sum);
    printf("\n Average of all input numbers = %.2f\n", average);
    getch();
}

Output:

sum avg array

C Program to Calculate the Sum of the Array Elements using Pointer:

A pointer is an object, whose value refers to another value stored elsewhere in the computer memory using its memory address. in this program, we use a pointer *ptr (pointer is declared by using * sign) which store initial address of numArray[].

#include<stdio.h>
#include<conio.h>

void main() 
{
   int numArray[10];
   int i, sum = 0;
   int *ptr;

   printf("\nEnter 10 elements : ");

   for (i = 0; i < 10; i++)
   scanf("%d", &numArray[i]);   //Accept the 10 elements from the user in the array.

   ptr = numArray; // a=&a[0] We are storing the address of the array into the pointer.

   for (i = 0; i < 10; i++)
   {
     sum = sum + *ptr;
     ptr++;
   }

 printf("The sum of array elements : %d", sum);
}

Output:

sum avg array1

C Program to Calculate Sum of all Elements of an Array using Pointers as Arguments:

One of the best things about pointers is that they allow functions to alter variables outside of their own scope. By passing a pointer to a function you can allow that function to read and write to the data stored in that variable. In this program, we use a pointer (*ptr) to catch an array address which passes through a function argument (addnum()).

#include <stdio.h>
void main() {
 int array[5] = { 100, 300, 800, 400, 1000 } ;

 int sum;
 clrscr();

 int addnum(int *ptr);

 sum = addnum(array);
 printf("Sum of all array elements = %d\n", sum);
 getch();
}
int addnum(int *ptr) {
 int index, total = 0;
 for (index = 0; index < 5; index++) {
 total += *(ptr + index);
 }
 return(total);
}

Output:

sum avg array2

 

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Subroto Mondal

Chief Coordinator HR&CR
I like Programming and New Technologies. And work with Linux.

One thought on “C Program calculates the sum & average of an array

  1. Pingback: Using Arrays C Language with Example - NHIT Tech Blog

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